![]() ![]() The re.sub(pattern, repl, string, count=0, flags=0) method returns a new string where all occurrences of the pattern in the old string are replaced by repl. The second output is the list of three matching substrings because the string ‘Python’ appears three times at the beginning of a line. The first output is the empty list because the string ‘Python’ does not appear at the beginning of the string. > re.findall('^Python', text, re.MULTILINE) Here’s an example showing both usages-without and with setting the re.MULTILINE flag: > import re You can specify that the caret operator matches the beginning of each line via the re.MULTILINE flag. ![]() For example, you may want to find all lines that start with ‘Python’ in a given string. However, you may want to match at the beginning of each line. So if you’ve got a multi-line string-for example, when reading a text file-it will still only match once: at the beginning of the string. The caret operator, per default, only applies to the start of a string. But in the next example, it does: > re.findall('^PYTHON', 'PYTHON! PYTHON is fun')Īlthough there are two occurrences of the substring ‘PYTHON’, there’s only one matching substring-at the beginning of the string.īut what if you want to match not only at the beginning of the string but at the beginning of each line in a multi-line string? In other words: Python Re Start-of-Line (^) Regex In the previous example, this doesn’t make any difference. The caret at the beginning of the pattern ‘^PYTHON’ ensures that you match the word Python only at the beginning of the string. The findall(pattern, string) method finds all occurrences of the pattern in the string. > re.findall('^PYTHON', 'PYTHON is fun.') For example, this is useful if you want to ensure that a pattern appears at the beginning of a string. You can use the caret operator ^ to match the beginning of the string. Regular expression not going beyond space pyhon how to#
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